ACKNOWLEDGEMENT:
Figure
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Source of Figure
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Figure 7
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intranet.dunstan.school.nz
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Figure 8
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www.youtube.com
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Oxidizing and Reducing Agents:
Table 4:
Oxidizing
Agent
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Reducing
Agent
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Causes Oxidation
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Causes Reduction
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Self-reduced
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Self-oxidized
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Example: Potassium Manganate (KMnO4)
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Example: Potassium Iodide (KI)
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Explanation:
Potassium Manganate forms a purple
coloured solution, because of Manganate in the +7 oxidation state forms purple
coloured compounds. It causes oxidation by gaining electrons and losing
Oxygen needed for Oxidation to take place. The gain of electrons reduces
Manganese from the oxidation state of +7 to +2. Manganese forms colourless
solutions in this oxidation state and thus the purple colour of the solution
vanishes to indicate that oxidation has taken place.
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Explanation:
Potassium iodide forms a colourless
solution. Iodide ions in -1 oxidation state, have reduction capabilities, by
losing electrons, to aid reduction. They are self-oxidized to Iodine
molecules. These molecules change the colour of the solution from colourless
to slight brown, to indicate that reduction has taken place.
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Figure 7:
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Figure 8:
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